Sequence of Partial Sums
Key Formula
{Sn}={S1,S2,S3,…}whereSn=k=1∑nak=a1+a2+a3+⋯+an
Where:
- Sn = The nth partial sum — the sum of the first n terms of the series
- ak = The kth term of the original series
- n = The number of terms being summed (a positive integer)
Worked Example
Problem: Find the first five terms of the sequence of partial sums for the series ∑k=1∞2k1.
Step 1: Identify the terms of the series. The kth term is ak=2k1, so the first several terms are 21,41,81,161,321,…
a1=21,a2=41,a3=81,a4=161,a5=321
Step 2: Compute S1, the first partial sum.
S1=a1=21
Step 3: Compute S2 and S3 by adding the next term each time.
S2=21+41=43,S3=43+81=87
Step 4: Continue for S4 and S5.
S4=87+161=1615,S5=1615+321=3231
Step 5: Write the sequence of partial sums. Notice each term follows the pattern Sn=1−2n1, and as n→∞, Sn→1. So the series converges to 1.
{Sn}={21,43,87,1615,3231,…}
Answer: The first five partial sums are 21,43,87,1615,3231. The sequence converges to 1.
Another Example
This example shows a telescoping series where you can find a closed-form formula for Sn and then take its limit, rather than just listing numerical values of partial sums.
Problem: Find a closed-form expression for the nth partial sum of the telescoping series ∑k=1∞(k1−k+11) and determine whether the series converges.
Step 1: Write out the partial sum Sn by expanding the first several terms.
Sn=(11−21)+(21−31)+(31−41)+⋯+(n1−n+11)
Step 2: Most terms cancel in pairs (this is why it is called a telescoping series). After cancellation, only the first and last parts remain.
Sn=1−n+11
Step 3: Check a few values: S1=1−21=21, S2=1−31=32, S3=1−41=43. These match direct computation.
{Sn}={21,32,43,54,…}
Step 4: Take the limit of the sequence of partial sums to determine convergence.
n→∞limSn=n→∞lim(1−n+11)=1
Answer: The nth partial sum is Sn=1−n+11, and the series converges to 1.
Frequently Asked Questions
What is the difference between a series and a sequence of partial sums?
A series is the expression ∑k=1∞ak, which represents the idea of adding infinitely many terms. The sequence of partial sums {S1,S2,S3,…} is the actual sequence you build by computing finite sums one term at a time. The series converges if and only if this sequence of partial sums converges to a finite limit.
How do you tell if a series converges using partial sums?
Compute (or find a formula for) the nth partial sum Sn, then evaluate limn→∞Sn. If this limit exists and is a finite number L, the series converges to L. If the limit does not exist or is infinite, the series diverges.
Can you always find a formula for the nth partial sum?
No. Closed-form expressions for Sn exist for certain types of series such as geometric series, telescoping series, and a few others. For most series, you cannot write Sn in a simple closed form, which is why convergence tests (like the ratio test or comparison test) are so important — they let you determine convergence without needing an explicit formula for Sn.
Sequence of Partial Sums vs. nth Partial Sum
| Sequence of Partial Sums | nth Partial Sum | |
|---|---|---|
| What it is | The entire sequence {S1,S2,S3,…} | A single value Sn for one particular n |
| Formula | {Sn}n=1∞ where each Sn=∑k=1nak | Sn=a1+a2+⋯+an |
| Purpose | Analyze convergence by studying the behavior of the whole sequence | Approximate the sum of a series using the first n terms |
| Example output | {21,43,87,…} (a list of values) | S3=87 (a single number) |
Why It Matters
The sequence of partial sums is the fundamental tool for defining what it means for an infinite series to converge. In calculus courses, you encounter it whenever you study geometric series, telescoping series, or power series representations of functions. Understanding this concept bridges the gap between finite addition (which you already know) and the idea of summing infinitely many terms.
Common Mistakes
Mistake: Confusing the original sequence {an} with the sequence of partial sums {Sn}.
Correction: The terms an are the individual pieces being added. The partial sums Sn are cumulative totals. For example, if an=2n1, then a3=81 but S3=87. These are very different sequences.
Mistake: Assuming that if an→0 then Sn must converge to a finite limit.
Correction: The terms approaching zero is necessary but not sufficient for convergence. The harmonic series ∑k1 has ak→0, yet Sn→∞. You must examine the limit of Sn itself (or use a convergence test) to determine whether the series converges.
Related Terms
- Sequence — A sequence of partial sums is itself a sequence
- nth Partial Sum — Each individual term in the sequence of partial sums
- Series — The sum whose convergence is determined by partial sums
- Convergence Tests — Methods used when closed-form partial sums are unavailable
- Infinite Series — Converges when its sequence of partial sums has a finite limit
- Geometric Series — A classic series with a known partial sum formula
- Telescoping Series — Series where partial sums simplify by cancellation

